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if [[ $EXIT_CODE -ne 0 ]]; then STEP_OK=$EXIT_CODE [[ -w /tmp ]] && echo $STEP_OK > /tmp/step.$$ if [[ -n $LOG_STEPS ]]; then local FILE=$(readlink -m "${BASH_SOURCE[1]}") local LINE=${BASH_LINENO[0]} echo "$FILE: Execution: $ ./tmp.sh touch: cannot touch '/root/test': Permission denied created file $ echo $? 0 As you can see after running the ./tmp.sh command the exit code was 0 which indicates Reply Link nixCraft August 5, 2008, 1:00 pmExit status is depend upon program or command. The above command will execute the ./tmp.sh script, and if the exit code is 0 the command echo "bam" will be executed. navigate here

Consider following shell script:#!/bin/bash echo -n "Enter user name : " read USR cut -d: -f1 /etc/passwd | grep "$USR" > /dev/null OUT=$? How could banks with multiple branches work in a world without quick communication? Especially if that script is used for the command line. For example, to determine whether a particular regular expression regex was present somewhere in a file options, we might apply grep(1) with its POSIX -q option to suppress output and just

Bash Exit Status Variable

A temporary variable is the standard and preferred way to get the effect you're looking for. Systems, Tools, and Terminal Science Search Main menu Skip to primary content HomeAboutLinux CryptoNCACUnidexUnix as IDEVim Koans Post navigation ← Previous Next → Testing exit values in Bash Posted on October Just place the following in a file: my_notify() { echo "exit code: $?" echo "PPID: $PPID" } Then source that file from your shell startup files. I am porting shell code from OpenVMS to Unix, and was searching for the equivalent to DCL's $status.

Let foo be a function that does not "return" (echo) a value, but it sets the exit code as usual. share|improve this answer edited Jun 14 '15 at 5:34 answered Jun 14 '15 at 1:03 mikeserv 37k341109 add a comment| up vote 8 down vote There are various options to handle share|improve this answer answered Mar 4 '11 at 16:11 John Kugelman 173k36306384 Didn't think of this, not the method I went with but it is quick and easy to Bash Check Error Code Of Last Command For example, you run the command cal: $ cal Now to see exit status of cal command type following command: $ echo $?

Any script that is useful in some fashion will inevitably be either used in another script, or wrapped with a bash one liner. I use this construct in scripts where i want to provide alternatives for the same command. Don't let this happen to you! Script: #!/bin/bash touch /root/test 2> /dev/null if [ $? -eq 0 ] then echo "Successfully created file" else echo "Could not create file" >&2 fi In the above revision of our

share|improve this answer edited Jun 13 '15 at 17:05 eadmaster 351414 answered Jun 13 '15 at 14:34 llua 3,582716 1 Valid for this particular example, but only usable if there Bash Error Code 255 This becomes more important as your programs get more complex and you start having scripts launching other scripts, etc. Actions such as printing to stdout on success and stderr on failure. My home country claims I am a dual national of another country, the country in question does not.

Bash Get Last Exit Code

It's generally more straightforward to simply write your own error handling using the methods above. should return the sudo exit status, but instead it always returns 0 (the exit code of the test). Bash Exit Status Variable Reply Link M P November 9, 2010, 1:23 pmVery helpful. Bash Get Exit Code Of Last Command deleted my comment. –pzkpfw Apr 21 at 4:38 add a comment| up vote 9 down vote Personally I much prefer to use a lightweight approach, as seen here; yell() { echo

share|improve this answer answered May 3 '15 at 22:12 niieani 9431017 add a comment| up vote 2 down vote Sorry that I can not make a comment to the first answer check over here Reply ↓ TaG November 23, 2012 at 7:41 pm Thanks! That is, the program's ability to handle situations in which something goes wrong. to negate the test as well, to prevent us having to use else as well: # Best if ! Bash Script Last Command Status

Ask Ubuntu works best with JavaScript enabled The Sarth Repository source control for my (useless) knowledge Menu Skip to content HomeAboutProjects check last exit status code in bash shell 4 Replies COMMAND_LAST # Will exit with status of last command.

$? reads the exit status of the last command share|improve this answer answered Oct 21 '12 at 16:39 Ignacio Vazquez-Abrams 443k62792950 add a comment| up vote 1 down vote One method to implement this could be to use EOF tag http://onlinetvsoftware.net/error-code/bash-error-code-127.php echo $? # Non-zero exit status returned -- command failed to execute.

If you'd apply the same artificial $(get_errnos) code to any other solutions (( exit 42 ); test "$(get_errnos)" -ne $? && echo $_) they also don't work. (You preferred to bring Bash Error Code Of Previous Command check exit code, 3. Meaning of "soul-sapping" Intuition behind Harmonic Analysis in Analytic Number Theory Verbs of buttons on websites Least Common Multiple Yes, of course I'm an adult!

It contains the current # line number.

So to check the exit status, we could write the script this way: # Check the exit status cd $some_directory if [ "$?" = "0" ]; then rm * else echo Your answer is absolutely correct for the above question. –mcmlxxxiii Aug 12 at 21:55 add a comment| up vote 22 down vote There is no special bash variable for that. $? If you're just asking out of simple curiosity, then the answer is no. Bash Error Code Handling Why is this important?

What happens if I don't specify an exit code In Linux any script run from the command line has an exit code. The Woz Monitor Video displays in Star Wars Which requires more energy: walking 1 km or cycling 1 km at the same speed? If grep command finds user name in /etc/passwd command output it would return exit status of zero. weblink This value is referred to as an exit code or exit status.

You can surround a variable name with curly braces (as with ${PROGNAME}) if you need to be sure it is separated from surrounding text. COMMAND_LAST # Will exit with status of last command.